Question

A pendulum clock has an iron pendulum $1$m long $({\alpha }_{iron}={10}_{-5}{/}^{o}C)$. if the temperature rises by ${10}^{o}C$,the clock

• A. Will lose $8$ seconds per day
• B. Will lose $4.32$ seconds per day
• C. Will gain $8$ seconds per day
• D. Will gain $4.32$ seconds per day

Answer 1

The correct option is B Will lose $4.32$ seconds per day

The clock get slow by $\frac{\alpha △T}{2}$ in $1s$

$\frac{\alpha △T}{2}=\frac{{10}^{-5}\times 10}{2}$

So, in $1$ day $=24\times 60\times 60s$

Clock will be slowed by $\frac{24\times 60\times 60\times {10}^{-5}\times 10}{2}=4.32s$