Question

A pendulum clock which shows correct time on earth has taken to the moon, now it will becomes.

• A. Correct time
• B. $6$ times faster
• C. $\sqrt{6}$ times slower
• D. None of these

Answer 1

The correct option is C $\sqrt{6}$ times slower

Time period by a pendulum clock,
$T=2\pi \sqrt{\frac{l}{g}}$
$\frac{T_{earth}}{T_{moon}}=\sqrt{\frac{g_m}{g_e}}=\sqrt{\frac{g_e/6}{g_e}}[\because g_m=\frac{g_e}{6}]$
$=\frac{1}{\sqrt{6}}$
$T_{moon}=\sqrt{6}{T}_e$ i.e., clock become slower.