Question

A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is 20 $m/s^2$ at a distance of $5m$ from the mean position. The time period of oscillation is

• A. $2\pi s$
• B. $\pi s$
• C. 2 s
• D. 1 s

Answer 1

The correct option is B $\pi s$

We know that the,
magnitude of acceleration in SHM
$|a|={\omega }^{2}x$
$20={\omega }^2\times 5$
$\Rightarrow \omega =2rad/s$

Time period $T=\frac{2\pi }{\omega }=\pi s$