Question

A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum $20m/s^2$ at a distance of $5m$ from the moving position. The time period of oscillation is?

• A. $2s$
• B. $2\pi s$
• C. $1s$
• D. $\pi s$

Answer 1

The correct option is D $\pi s$

Since in SHM, magnitude of acceleration is given as

$a={\omega }^{2}x$

$20={\omega }^2\times 5$

$\omega =2$

Now, Time Period (T),

$T=\frac{2\pi }{\omega }$

$T=\pi s$