A pendulum is suspended from the roof of a railway compartment moving horizontally with acceleration $a$ . If the pendulum makes an angle $θ$ with the vertical then (acceleration due to gravity=g)

a = g tan θ

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g = a tan θ

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a = g sin θ

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g = a sin θ

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Solution

The correct option is A $a = g tan θ$
From FDB of pendulum , $T sin θ = m a . . . . (1)$
and $T cos θ = m g . . . . (2)$
So, $(1) / (2) \Rightarrow tan θ = a / g$ or $a = g tan θ$

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A pendulum is suspended from the roof of a railway compartment moving horizontally with acceleration a. If the pendulum makes an angle θ with the vertical then (acceleration due to gravity=g)

The correct option is A a=gtanθFrom FDB of pendulum , Tsinθ=ma....(1) and Tcosθ=mg....(2) So, (1)/(2)⇒tanθ=a/g or a=gtanθ

A pendulum is suspended from the roof of a railway compartment moving horizontally with acceleration $a$ . If the pendulum makes an angle $θ$ with the vertical then (acceleration due to gravity=g)

The correct option is A $a = g tan θ$
From FDB of pendulum , $T sin θ = m a . . . . (1)$
and $T cos θ = m g . . . . (2)$
So, $(1) / (2) \Rightarrow tan θ = a / g$ or $a = g tan θ$