A pendulum oscillates 40 times in 4 seconds, and then the time period obtained is

0.8 sec

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10 sec

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4 sec

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0.1 sec

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Solution

The correct option is D
0.1 sec

Frequency = $\frac{N u m b e r o f o s c i l l a t i o n s}{T i m e t a k e n}$
F = $\frac{40}{4}$ = 10 Hz.
So, Time Period = $\frac{1}{f}$ = $\frac{1}{10}$ = 0.1 sec.

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Question 5
A pendulum oscillates 40 times in 4 seconds. Find its time period and frequency.

The number of oscillations per second is called the Time Peroid of oscillation

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