Question

# A pendulum oscillates 40 times in 4 seconds. Find its time period and frequency

Open in App
Solution

## Step (1) Given:No. of oscillations, $v=40$Time taken, $t=4seconds.$Step (2) Finding the time period, T using the formula:We know that time period, $T=\frac{timetakenforno.ofoscillations}{no.ofoscillations.}$The time period, $T$ of the given pendulum, is $=\frac{4}{40}\phantom{\rule{0ex}{0ex}}=\frac{1}{10}thofasecond.$Therefore, the time period of the given pendulum is $\frac{1}{10}sec\left(or\right)0.1sec$Step (3): Finding the frequency, $v$ of the pendulum:We know that $Frequency=\frac{\left(NumberofOscillations\right)}{\left(Timetaken\right)}\phantom{\rule{0ex}{0ex}}Frequencyofthegivenpendulum=\left(\frac{40}{4}\right)\phantom{\rule{0ex}{0ex}}=10Hz.$Hence, the frequency of the given pendulum is 10 Hz.

Suggest Corrections
30
Explore more