A pendulum string of length $l$ is moved upto a horizontal position and released as shown in figure. If the mass of pendulum is $m$ , then what is the minimum strength of the string that can withstand the tension as the pendulum passes through the position of equilibrium?
(neglect mass of the string and air resistance)

m g

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2 m g

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3 m g

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5 m g

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Solution

The correct option is C $3 m g$
We have, $T - m g = \frac{m v^{2}}{I}$
$v^{2} = 2 g I \Rightarrow T = m g + \frac{m 2 g I}{I} = 3 m g$

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The correct option is C 3mgWe have, T−mg=mv2Iv2=2gI⇒T=mg+m2gII=3mg

The correct option is C $3 m g$
We have, $T - m g = \frac{m v^{2}}{I}$
$v^{2} = 2 g I \Rightarrow T = m g + \frac{m 2 g I}{I} = 3 m g$