A perfect gas at $27^{\circ} C$ is heated at constant pressure so as to triple its volume. The temperature of the gas will be

81°C

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900°C

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627°C

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450°C

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Solution

The correct option is C
627°C

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}} \frac{V}{300} = \frac{3 V}{T_{2}} T_{2} = 900 K = 627^{0} C$

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