A perfect gas contained in a cylinder is kept in vacuum. If the cylinder suddenly bursts, then the temperature of the gas
A
remains constant
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B
becomes zero
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C
increases
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D
decreases
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Solution
The correct option is A remains constant Pext=0 No Work done since there is no external force. Also there is no heat supply to the cylinder. Hence, from first law of thermodynamics change in internal energy is zero. Change in internal energy of ideal gas is depends only on the change in temperature of the gas. Hence temperature remains same.