A perfect square number can never have the digit ____ at the units place.

1

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4

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8

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9

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Solution

The correct option is D $8$
As we know that all the perfect square number ends with $1, 4, 9, 6, 5, 00$
So, a number having $2, 3, 7$ or $8$ at unit's place is never a perfect square.

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The last digit of a perfect square can never be

A. 1

B. 3

C. 5

D. 9

6

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