Question

A permanent magnet in the shape of a thin cylinder of length $10$cm has magnetisation $\left(M\right)={10}^{6}A{m}^{-1}$. It's magnetization current $I_M$ will be then

• A. ${10}^5$A
• B. ${10}^6$A
• C. ${10}^7$A
• D. ${10}^8$A

Answer 1

Answer: (A)

${10}^5$A

Given,

$M={10}^{6}A/m$

$l=10cm=0.1m$

Magnetization, $M=\frac{I_M}{l}$

$I_M=Ml={10}^6\times 0.1$

$I_M={10}^{5}A$

The correct option is A.