A perpendicular is drawn to a line segment $¯ ¯¯¯¯¯ ¯ I P$ at N using protractor and point M is marked on perpendicular then

¯ ¯¯¯¯¯¯¯¯ ¯ M P ⊥ ¯ ¯¯¯¯¯¯¯ ¯ N P

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¯ ¯¯¯¯¯¯¯¯¯ ¯ M N ⊥ P

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M ⊥ P

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¯ ¯¯¯¯¯¯¯¯¯ ¯ M N ⊥ ¯ ¯¯¯¯¯¯¯ ¯ N P

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Solution

The correct option is C $¯ ¯¯¯¯¯¯¯¯¯ ¯ M N ⊥ ¯ ¯¯¯¯¯¯¯ ¯ N P$
A perpendicular is drawn to a line segment $¯ ¯¯¯¯¯ ¯ I P$ at $N$ using protractor and point $M$ is marked on perpendicular then $¯ ¯¯¯¯¯¯¯¯¯ ¯ M N ⊥ ¯ ¯¯¯¯¯¯¯ ¯ N P$

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Similar questions

¯ ¯¯¯¯¯¯¯¯¯ ¯ M N

¯ ¯¯¯¯¯¯¯¯¯ ¯ M N

Construct a triangle MNP in which MN = 4.5 cm, MP = 5.2 cm and length of perpendicular from M on NP is 3.8 cm.

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\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1

M & N

M P & N P

P

P

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