CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A person (40 kg) is managing to be at rest between two vertical walls by pressing one wall A by his hands and feet and the other wall B by his back (figure 6-E11). Assume that the friction coefficient between his body and the walls is 0.8 and that limiting friction acts at all the contacts. (a) Show that the person pushes the two walls with equal force. (b) Find the normal force exerted by either wall on the person. Take g=10m/s2.
1281154_4395089014d64d399d5b80b32d6bed74.png

Open in App
Solution

Let N1 is the normal exerted by right wall &
N2 is the normal exerted by left wall.
there is equilibrium in x direction.
N1=N2=N
Now,
0.8×N×2=40gN=40002×8=10004=250N
Normal force exerted by either is 250N.

flag
Suggest Corrections
thumbs-up
1
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Instantaneous Axis of Rotation
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon