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Question

A person A can clearly see objects between 25 cm and 200 cm. Which of the following may represent the range of clear vision for a person B having muscles stronger than A, but all other parameters of eye identical to that of A?

A
25 cm to 200 cm
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B
18 cm to 200 cm
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C
25 cm to 300 cm
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D
18 cm to 300 cm
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Solution

The correct option is B 18 cm to 200 cm
Stronger muscles of B will allow the person to contract the eye lens more than compared to the person A. This will increase the radius of curvature of the eye lens and hence this will increase the focus of the lens. So the person B would be able to see closer objects more clearly.

But person B will see same as person A, when looking the far object because stronger muscle does not help in relaxing the eye lens to see for objects.

So, person B can see the objects between 18 cm to 200 cm.

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (B) is the correct answer.
Why this question ?
Concept : To see nearby object, strong muscle and more focal length of the eye lens is required. To see far objects clearly, relaxed eye and less focal length of the lens is required.



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Q. The ciliary muscles of eye control the curvature of the lens in the eye and hence and alter the effective focal length of the system. When the muscles are fully relaxed, the focal length is maximum. When the muscles are strained, the curvature of lens increases. That means, radius of curvature decreases and focal length decreases. For a clear vision, the image must be on the retina. The image distance is therefore fixed for clear vision and it equals the distance of retina from eye lens. It is about 2.5 cm for a grown up person.
A person can theoretically have clear vision of an object situated at any large distance from the eye. The smallest distance at which a person can clearly see is related to minimum possible focal length. The ciliary muscles are most strained in this position. For an average grown up person, minimum distance of the object should be around 25 cm.
A person suffering from eye defects uses spectacles (eye glass). The function of lens of spectacles is to form the image of the objects within the range in which the person can see clearly. The image of the spectacle lens becomes object for the eye lens and whose image is formed on the retina.
The number of spectacle lens used for the remedy of eye defect is decided by the power of the lens required and the number of spectacle lens is equal to the numerical value of the power of lens with sign. For example, if power of the lens required is +3D (converging lens of focal length 100/3 cm), then number of lens will be +3.
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