A person can do a job as fast as his two sons working together. If one son does the job in 6 days and the other in 12 days, how many days does it take the father to do the job?

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Solution

Let the father complete the job in $x$ days.
Given, Father's 1 days' job = One son's one days' job + Second son's one days' job
$\Rightarrow \frac{1}{x} = \frac{1}{6} + \frac{1}{12} = \frac{2 + 1}{12} = \frac{3}{12} = \frac{1}{4}$
$∴$ Father can do the job in 4 days.

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A person can do a job as fast as his two sons working together. If one son does the job in 6 days and the other in 12 days, how many days does it take the father to do the job?

Let the father complete the job in x days.Given, Father's 1 days' job = One son's one days' job + Second son's one days' job⇒1x=16+112=2+112=312=14∴ Father can do the job in 4 days.

Let the father complete the job in $x$ days.
Given, Father's 1 days' job = One son's one days' job + Second son's one days' job
$\Rightarrow \frac{1}{x} = \frac{1}{6} + \frac{1}{12} = \frac{2 + 1}{12} = \frac{3}{12} = \frac{1}{4}$
$∴$ Father can do the job in 4 days.