A person can hear frequencies only below $10 k H z$ . A steel piano wire $50 c m$ long of mass $5 g$ is stretched with a tension of $400 N .$ The number of the highest overtone of the sound produced by this piano wire that the person can hear is

48

No worries! We‘ve got your back. Try BYJU‘S free classes today!

50

No worries! We‘ve got your back. Try BYJU‘S free classes today!

49

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

51

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $49$
$ν = \frac{n}{2 l} \sqrt{\frac{T}{m}} = \frac{n}{2 \times 0.5} \sqrt{\frac{400}{0.01}} = 200 n$
The person can hear only if
$ν < 10000$ Hz.
$\Rightarrow 200 n < 10000 \Rightarrow n < 50$

Suggest Corrections

Similar questions

Q. A steel wire

0.5

metre long and of mass

5 \times 10^{- 3} k g

is stretched with a tension

400 N

. What is the number of highest overtone that could be heard by a person who can hear frequencies up to

10 k H z

Q. A piano wire

0.5 m

long and mass

5 g m

is stretched by a tension of

400 N

. The number of highest overtone that can be heard by a person is

A steel wire fixed at both ends has a fundamentd: frequency of 200 Hz. A person can hear sound maximum frequency 14 kHz. What is the highest harmonic that can be played on this string which is audible to the person ?

Q. A steel wire fixed at both ends has a fundamental frequency of 200 Hz. A person can hear sound of maximum frequency 14 kHz. What is the highest harmonic that can be played on this string which is audible to the person?

Q. A person is tuning a piano, using

512 H z

tuning fork, trying to match this frequency to the frequency of the note produced by the piano. The person hears a pitch close to

512 H z

that gets loud and soft four times each second.
What is a possible value of the current frequency of the note produced by the piano?

Join BYJU'S Learning Program

A person can hear frequencies only below 10kHz. A steel piano wire 50cm long of mass 5g is stretched with a tension of 400N. The number of the highest overtone of the sound produced by this piano wire that the person can hear is

The correct option is B 49ν=n2l√Tm=n2×0.5√4000.01=200nThe person can hear only if ν<10000 Hz.⇒200n<10000⇒n<50

A person can hear frequencies only below $10 k H z$ . A steel piano wire $50 c m$ long of mass $5 g$ is stretched with a tension of $400 N .$ The number of the highest overtone of the sound produced by this piano wire that the person can hear is

The correct option is B $49$
$ν = \frac{n}{2 l} \sqrt{\frac{T}{m}} = \frac{n}{2 \times 0.5} \sqrt{\frac{400}{0.01}} = 200 n$
The person can hear only if
$ν < 10000$ Hz.
$\Rightarrow 200 n < 10000 \Rightarrow n < 50$