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Question

A person can see clearly objects only when they lie between 50 cm and 400 cm from his eyes. In order to increase the maximum distance of distinct vision to infinity, the type and power of the correcting lens, the person has to use, will be?

A
Convex, +2.25 dioptre
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B
Concave, 0.25 dioptre
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C
Concave, 0.2 dioptre
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D
Convex, +0.15 dioptre
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Solution

The correct option is B Concave, 0.25 dioptre
Maximum distance of distinct vision =400 cm
So, image of object at infinity is to be formed at 400 cm or 4 m
Using lens formula, P=1f=1v1u
141=1f
P=1f=0.25 D
–ive implies concave mirror

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