A person can see clearly objects only when they lie between 50cm and 400cm from his eyes. In order to increase the maximum distance of distinct vision to infinity, the type and power of the correcting lens, the person has to use, will be?
A
Convex, +2.25 dioptre
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B
Concave, −0.25 dioptre
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C
Concave, −0.2 dioptre
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D
Convex, +0.15 dioptre
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Solution
The correct option is B Concave, −0.25 dioptre Maximum distance of distinct vision =400cm
So, image of object at infinity is to be formed at 400cm or 4m
Using lens formula, P=1f=1v−1u 1−4−1∞=1f P=1f=−0.25 D
–ive implies concave mirror