Question

A person can throw a stone to a maximum distance of 100 m. The greatest height to which he can throw the stone is:-

• A. 100 m
• B. 75 m
• C. 50 m
• D. 25 m

Answer 1

The correct option is D 25 m

Maximum height is given by H $=\frac{u^{2}si{n}^2\theta }{2g}$

Range is given as R $=\frac{u^{2}sin2\theta }{g}=100m\left(given\right)$

Maximum height is attained at 45 degree launch, so $\theta =45$

$u^2=1000$ and Maximum height is 25 m by formula of H.