A person cannot see distinctly at the distance less than one metre. Calculate the power of the lens that he should use to read a book at a distance of 25 cm

[CPMT 1977; MP PET 1985, 88; MP PMT 1990]

+ 3.0 D

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

+ 0.125 D

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 3.0 D

No worries! We‘ve got your back. Try BYJU‘S free classes today!

+ 4.0 D

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A + 3.0 D
$P = \frac{1}{f} = \frac{1}{v} - \frac{1}{u} .$
Applying sign convention,
$P = \frac{1}{f} = \frac{1}{- 100} - \frac{1}{- 25} = \frac{3}{100} = + 3 D .$

Suggest Corrections

Similar questions

A person cannot see distinctly at the distance less than one metre. Calculate the power of the lens that he should use to read a book at a distance of 25 cm

[CPMT 1977; MP PET 1985, 88; MP PMT 1990]

Q. A man can see distinctly from a distance of

0.5

metre. If he wants to read a book placed at a distance of

25 c m

, then what should be the power of lens ?

Q. A man can see distinctly from a distance of

0.5 m

. If he wants to read a book placed at a distance of

25 c m

, then what kind of lens should he use?

A man who cannot see clearly beyond 5 m wants to see stars clearly. He should use a lens of focal length

[MP PET/PMT 1988; Pb. PET 2003]

Q. A man cannot see objects distinctly at a distance less than 1 metre. He is suffering from

Join BYJU'S Learning Program

A person cannot see distinctly at the distance less than one metre. Calculate the power of the lens that he should use to read a book at a distance of 25 cm [CPMT 1977; MP PET 1985, 88; MP PMT 1990]

The correct option is A + 3.0 DP=1f=1v−1u. Applying sign convention, P=1f=1−100−1−25=3100=+3D.

A person cannot see distinctly at the distance less than one metre. Calculate the power of the lens that he should use to read a book at a distance of 25 cm

[CPMT 1977; MP PET 1985, 88; MP PMT 1990]

The correct option is A + 3.0 D
$P = \frac{1}{f} = \frac{1}{v} - \frac{1}{u} .$
Applying sign convention,
$P = \frac{1}{f} = \frac{1}{- 100} - \frac{1}{- 25} = \frac{3}{100} = + 3 D .$