wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A person cannot see distinctly objects kept beyond 2m. This defect can be corrected by using lens of power


A

0.5 D

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

-0.5 D

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

0.2 D

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

-0.2 D

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

-0.5 D


Step 1: Given Data

  1. As per sign convention:
  2. The normal position of the far object is D=-
  3. The position till the far object is seen is d=-2cm

Step 2: Calculation of power of the lens

Apply the lens formula to calculate the focal length of the lens:
1f=1d-1D=1-2+1f=-2cm

Power of the lens is defined as the inverse of the focal length of the lens.

P=1f=1-2cm=-0.5D

Therefore, the power of the lens is -0.5 D.

Hence, option (b) is correct


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Total Internal Reflection
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon