Question

A person divided Rs. $10,800$ among his three sons in the ratio $3:4:5$. Second son kept Rs. $1000$ for himself, gave Rs. $600$ to his wife and divided the remaining money among his two daughters in the ratio $11:9$. Then one of his daughter's received

• A. Rs. $1000$
• B. Rs. $1050$
• C. Rs. $1100$
• D. Rs. $1150$

Answer 1

The correct option is C Rs. $1100$

Second son's share $=\frac{4}{(3+4+5)}\times$Rs. $10,800$
$=\frac{4}{12}\times$ Rs $,10,800=$ Rs. $3600$
Remaining money with him $=$ Rs. $3600-$ Rs. $(1000+600)$
$=$ Rs. $2000$.
Both the daughter's share are $\frac{11}{20}\times$ Rs. $2000$ and $\frac{9}{20}\times$ Rs. $2000$

$=$ Rs. $1100$ and Rs. $900$.