A person eats a 100 g of rice and 100 g of flour in a day- He eats pulses equal to 1-3rd of the total quantity of rice and flour- What is the quantity of pulses eaten by him in 6 days-

Rice eaten in a day= 100 g Flour eaten in a day= 100g Total nbsp;Quantity of rice and flour eaten in a day = 200 g Quantity of rice and pulses eaten in 6 days ...

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Mathematics

Applications of HCF & LCM in Real-World Problems

A person eats...

Question

A person eats a 100 g of rice and 100 g of flour in a day. He eats pulses equal to ${\frac{1}{3}}^{r d}$ of the total quantity of rice and flour. What is the quantity of pulses eaten by him in 6 days?

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Solution

Rice eaten in a day= 100 g
Flour eaten in a day= 100g
Total Quantity of rice and flour eaten in a day = 200 g
Quantity of rice and pulses eaten in 6 days = 200 x 6
= 1200 g

So, the quantity of pulses eaten by him in 6 days
= ${\frac{1}{3}}^{r d}$ of 1200 g
= 1200 $\div$ 3
= 400 g

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A person eats a 100 g of rice and 100 g of flour in a day. He eats pulses equal to 13rd of the total quantity of rice and flour. What is the quantity of pulses eaten by him in 6 days?

Rice eaten in a day= 100 g Flour eaten in a day= 100g Total Quantity of rice and flour eaten in a day = 200 g Quantity of rice and pulses eaten in 6 days = 200 x 6 = 1200 g So, the quantity of pulses eaten by him in 6 days = 13rd of 1200 g = 1200 ÷ 3 = 400 g

A person eats a 100 g of rice and 100 g of flour in a day. He eats pulses equal to ${\frac{1}{3}}^{r d}$ of the total quantity of rice and flour. What is the quantity of pulses eaten by him in 6 days?

Rice eaten in a day= 100 g
Flour eaten in a day= 100g
Total Quantity of rice and flour eaten in a day = 200 g
Quantity of rice and pulses eaten in 6 days = 200 x 6
= 1200 g

So, the quantity of pulses eaten by him in 6 days
= ${\frac{1}{3}}^{r d}$ of 1200 g
= 1200 $\div$ 3
= 400 g