A person goes 10 km north and 20 km east. What will be displacement from initial point

22.36 km

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Solution

The correct option is A 22.36 km

$\to A C = \to A B + \to B C A C = \sqrt{(A B)^{2} + (B C)^{2}} = \sqrt{(10)^{2} + (20)^{2}} = \sqrt{100 + 400} = \sqrt{500} = 22.36 k m$

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A person goes 10 km north and 20 km east. What will be displacement from initial point

The correct option is A 22.36 km →AC=→AB+→BCAC=√(AB)2+(BC)2=√(10)2+(20)2=√100+400=√500=22.36km

The correct option is A 22.36 km

$\to A C = \to A B + \to B C A C = \sqrt{(A B)^{2} + (B C)^{2}} = \sqrt{(10)^{2} + (20)^{2}} = \sqrt{100 + 400} = \sqrt{500} = 22.36 k m$