A person holds a bucket of weight $60 N$ . He walks $7 m$ along the horizontal and then climbs a vertical distance of $5 m$ . The work done by the man against the gravity force is:

300 J

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420 J

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720 J

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none of the above

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Solution

The correct option is A $300 J$
By work Energy theorem,
$W_{n e t} = W_{h o r i z o n t a l} + W_{v e r t .} = 0 + 5 \times 60 = 300 J$
horizontal work is zero as the force is in vertical direction and the motion is in horizontal direction.

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A person holds a bucket of weight 60N. He walks 7m along the horizontal and then climbs a vertical distance of 5m. The work done by the man against the gravity force is:

The correct option is A 300JBy work Energy theorem,Wnet=Whorizontal+Wvert.=0+5×60=300Jhorizontal work is zero as the force is in vertical direction and the motion is in horizontal direction.

A person holds a bucket of weight $60 N$ . He walks $7 m$ along the horizontal and then climbs a vertical distance of $5 m$ . The work done by the man against the gravity force is:

The correct option is A $300 J$
By work Energy theorem,
$W_{n e t} = W_{h o r i z o n t a l} + W_{v e r t .} = 0 + 5 \times 60 = 300 J$
horizontal work is zero as the force is in vertical direction and the motion is in horizontal direction.