A person invites a group of 10 friends at dinner and makes them to sit on 2 round table's with 5 persons on each table . The number of ways in which he can arrange the guests is:
The number of ways of selection of 5 friends for first table can be done in 10C5 ways.
Remaining 5 friends can be arranged on second table.
The total number of permutations of 5 guests on each table is 4!
Hence, the total number of arrangements
= 10C5×4!×4!
=10!(5!×5!)×4!×4!
=10!25.