A person is at a distance of d m from a bus when the bus starts with a uni-form acceleration of $0.05 m s^{- 2}$ . The velocity with which the person should run towards the bus is $1.5 m s^{- 1}$ to catch the bus in $40 s$ . Find the value of d.

50m

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10m

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20m

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40m

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Solution

The correct option is C
20m

Step 1: Given data,
The initial acceleration of the bus $= 0.05 m s^{- 2}$
The velocity of the person $= 1.5 m s^{- 1}$
Time is taken to catch $= 40 s$
The initial distance between the person and the bus is d m.
Step 2: Solution,
Distance traveled by bus in 40 s,
$s = 0 + \frac{1}{2} \times 0.05 \times 40 \times 40$
$s = 40 m$
Distance traveled by the person in 40 s,
$s = 1.5 \times 40 = 60 m .$
So the distance d between them is $60 - 40 = 20 m .$
Hence the correct option is (C) 20 m.

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A person is at a distance of d m from a bus when the bus starts with a uni-form acceleration of 0.05ms-2. The velocity with which the person should run towards the bus is1.5ms-1 to catch the bus in 40s. Find the value of d.

A person is at a distance of d m from a bus when the bus starts with a uni-form acceleration of $0.05 m s^{- 2}$ . The velocity with which the person should run towards the bus is $1.5 m s^{- 1}$ to catch the bus in $40 s$ . Find the value of d.