Question

A person is climbing on a vertical pole of height $18\text{m}$. Starting from the height of $2\text{m}$ of the pole, if he climbs $0.5\text{m}$ in one second, how far will he be after $10\text{s}$ from the base of the pole?

• A. $5\text{m}$
• B. $7\text{m}$
• C. $2\text{m}$
• D. $8\text{m}$

Answer 1

The correct option is B $7\text{m}$

As per the question, person climbs $0.5\text{m}$ in one second. So, in $10\text{s}$, he will climb $10\times 0.5=5\text{m}$ up the pole.
Since, he starts climbing from the height of $2\text{m}$, therefore, from the base of the pole he will be at the height of $5+2=7\text{m}$