A person is cycling parallel to a railway track at a speed of $10$ km/hr. A train travelling in the same direction at $46$ km/hr, passes him in $22$ sec. Find the length of the train .

120

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220

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150

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180

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Solution

The correct option is C $220$ m
Speed of cyclist $= 10$ km/hr
Distance travelled in $22 s e c = 10000 \times \frac{22}{360} = 61.1$ m
Speed of $= 46$ km/hr
Distance travelled by train $= 46000 \times \frac{22}{3600} = 281.1$ m
Since the train crosses the cyclist at $22$ secs, the distance of the train $281.1 - 61.1 = 220$ m

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A person is cycling parallel to a railway track at a speed of 10 km/hr. A train travelling in the same direction at 46 km/hr, passes him in 22 sec. Find the length of the train .

The correct option is C 220 mSpeed of cyclist =10 km/hrDistance travelled in 22sec=10000×22360=61.1 mSpeed of =46 km/hrDistance travelled by train =46000×223600=281.1 mSince the train crosses the cyclist at 22 secs, the distance of the train 281.1−61.1=220m

A person is cycling parallel to a railway track at a speed of $10$ km/hr. A train travelling in the same direction at $46$ km/hr, passes him in $22$ sec. Find the length of the train .