A person is painting has house walls. He stands on a ladder with a bucket containing paint in one hand and a brush in other. Suddenly the bucket slips from his hand and falls down on the floor. If the bucket with the paint had a mass of 6.0 kg and was at a height of 2.0 m at the time it slipped, how much gravitational potential energy is lost together with the paint ?

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Solution

$m = 6 m, h = 2 m$

P.E at a height, $h = m g h$

$= 6 \times (9.8) \times 2$

$= 117.6 J$

P.E at floor=0

Loss in P.E $= 117 - 0$

$= 117.6 J \approx 118 J$

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m=6 m,h=2 m P.E at a height,h=mgh =6×(9.8)×2 =117.6 J P.E at floor=0 Loss in P.E =117−0 =117.6 J≈118 J

$m = 6 m, h = 2 m$

P.E at a height, $h = m g h$

$= 6 \times (9.8) \times 2$

$= 117.6 J$

P.E at floor=0

Loss in P.E $= 117 - 0$

$= 117.6 J \approx 118 J$