Question

A person moves a certain distance in a certain time. If 1/3 of the distance is covered in 2/3 of the time with speed $V_1$, and the rest of the 2/3 distance in 1/3 of the time speed $V_2$, then $V_1/V_2$ is

• A. 1/2
• B. 1/4
• C. 4/9
• D. 2/9

Answer 1

The correct option is B 1/4

Let total distance is x
$t_2=\frac{2t}{3}$
$t_2=\frac{1}{3}$
distance is $\frac{x}{3}$
distance is $\frac{2x}{3}$
$Speed=V_1$
$Speed=V_2$
$V_1=\frac{x\times 31}{3\times 2t}$
$V_2=\frac{2x\times 3}{3\times t}$
$\frac{V_1}{V_2}=\frac{\frac{x}{2t}}{\frac{2x}{t}}=\frac{1}{4}$