A person near point is 50cm and his far point is 3m. Powers of the lenses he requires for (i) reading (ii) seeing distant stars are
A
−2D and 0.33D
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B
2D and 0.33D
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C
−2D and 3D
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D
2D and −3D
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Solution
The correct option is D2D and −3D For correcting the near point, required focal length f=50×25(50−25)=50cm So power P=10050=+2D For correcting the far point, required focal length f=− ( defected far point ) =−3m ∴P=−13D=−0.33D