Question

A person observes the angle of elevation of the top of a 60m tower from a point on the level ground to be 60${}^{\circ }$. Find the distance between the person and the foot of the tower.

• A. 30 m
• B. 20$\sqrt{3}$ m
• C. 20 m
• D. 60 m

Answer 1

The correct option is B

20$\sqrt{3}$ m

In $\Delta ABC$, tan(60${}^{\circ }$) = $\frac{BC}{AB}$

$\Rightarrow$ $\sqrt{3}=\frac{60}{x}$

$\Rightarrow$ x = 20$\sqrt{3}$

$\Rightarrow$ Distance between the person and the tower = x = 20$\sqrt{3}$m.