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Standard XII

Physics

Ropes

A person of m...

Question

A person of mass $40 k g$ stands on a weighing scale on a lift. If the lift is ascending upwards with an uniform acceleration of $5 m / s^{2}$ . What should be the reading of the weighing scale ? (g = $10 m / s^{2}$ )

k g . w t

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200

k g . w t

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400

k g . w t

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k g . w t

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Solution

The correct option is B 60 $k g . w t$
Given,
$m = 40 k g$
$a = 5 m / s^{2}$
$g = 10 m / s^{2}$
Apparent weight,
$R = m (a + g)$
$R = 40 (10 + 5) = 600 k g m / s^{2}$
Mass, $M = \frac{R}{g}$
$M = \frac{600}{10} = 60 k g w t$
The correct option is D.

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A person of mass 40kg stands on a weighing scale on a lift. If the lift is ascending upwards with an uniform acceleration of 5m/s2. What should be the reading of the weighing scale ? (g =10m/s2)

The correct option is B 60 kg.wtGiven,m=40kga=5m/s2g=10m/s2Apparent weight,R=m(a+g)R=40(10+5)=600kgm/s2Mass, M=RgM=60010=60kgwtThe correct option is D.

A person of mass $40 k g$ stands on a weighing scale on a lift. If the lift is ascending upwards with an uniform acceleration of $5 m / s^{2}$ . What should be the reading of the weighing scale ? (g = $10 m / s^{2}$ )

The correct option is B 60 $k g . w t$
Given,
$m = 40 k g$
$a = 5 m / s^{2}$
$g = 10 m / s^{2}$
Apparent weight,
$R = m (a + g)$
$R = 40 (10 + 5) = 600 k g m / s^{2}$
Mass, $M = \frac{R}{g}$
$M = \frac{600}{10} = 60 k g w t$
The correct option is D.