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Question

# A person on a trip has a choice between private car and public tarnsport. The probability of using a private car is 0.45. While using the public transport further choices available are bus and metro, out of which the probability of commuting by a bus is 0.55. In such a situation, the probability (rounded up to two decimals) of using a car, bus and metro respectively would be

A
0.45, 0.30 and 0.25
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B
0.45, 0.25 and 0.30
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C
0.45, 0.55 and 0.00
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D
0.45, 0.35 and 0.20
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Solution

## The correct option is A 0.45, 0.30 and 0.25Obviously, probability of using a car = 0.45 Probability of using a bus = Probability of using public transport × prob. of commuting by a bus = (1 - 0.45) × (0.55) = 0.3025 ≃0.30 Probability of using a metro = (Prob. of using public transport) × (Prob. of commuting by metro) = (1 - 0.45) (1 - 0.55) = (0.2475) ≃0.25

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