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Question

A person on a trip has a choice between private car and public tarnsport. The probability of using a private car is 0.45. While using the public transport further choices available are bus and metro, out of which the probability of commuting by a bus is 0.55. In such a situation, the probability (rounded up to two decimals) of using a car, bus and metro respectively would be

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Solution

The correct option is **A** 0.45, 0.30 and 0.25

Obviously, probability of using a car = 0.45

Probability of using a bus = Probability of using public transport × prob. of commuting by a bus

= (1 - 0.45) × (0.55)

= 0.3025

≃0.30

Probability of using a metro = (Prob. of using public transport) × (Prob. of commuting by metro)

= (1 - 0.45) (1 - 0.55)

= (0.2475)

≃0.25

Obviously, probability of using a car = 0.45

Probability of using a bus = Probability of using public transport × prob. of commuting by a bus

= (1 - 0.45) × (0.55)

= 0.3025

≃0.30

Probability of using a metro = (Prob. of using public transport) × (Prob. of commuting by metro)

= (1 - 0.45) (1 - 0.55)

= (0.2475)

≃0.25

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