A person on the surface of the moon:
The value of ge on the surface of moon will be,
g′=g(1+hR)−2
After putting the values of g,h,R
we get the value of g′ as,
g′=.0026m/s2
This is almost negligible and can’t be felt on the person standing on moon.
Thus, a person on the surface of the moon does not feel the effect of earth's gravity because the gravity due to moon is much stronger.