A person opens an account with 50 and starts depositing every day double the amount he has deposited on the previous day. Then find the amount he has deposited on the 10th day from the beginning.

25000

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25600

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28500

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26500

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Solution

The correct option is A 25600
The given situation is a Geometric Progression, with first terms $a = 50$ and common ratio $r = 2$
For a GP, the $n t h$ term is given by $T_{n} = a r^{n - 1}$
So, amount deposited on the $10$ th day $= T_{10} = a r^{10 - 1} = 50 \times 2^{9} = 50 \times 512 = 25, 600$

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Manu has Rs. 8000 in his savings account on Sunday. He deposited Rs. 1000, the next day. Represent his deposit by an integer:

1 s t

R s .100

2 n d

R s .300

3 r d

R s .600

4 t h

R s .1000

15 t h

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