You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VII

Physics

Measurement of Volume

A person requ...

Question

A person requires $2870 K c a l$ of energy to lead normal daily life. If heat of combustion of cane sugar is $- 1349 K c a l$ , then his daily consumption of sugar is:

728 g

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.728 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

342 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.342 g

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $728 g$
Molar mass of cane sugar $(C_{12} H_{22} O_{11})$ is 342.2965 g/mol

The Heat of combustion reaction for sugar.

For 1 mol it is -1349 Kcal.

For 2870 Kcal total moles would be = 2870/1349 = 2.127 moles.

Weight of sugar $= 2.127 \times 342 = 727.6 = 728 g$

Suggest Corrections

Similar questions

Q. On average a person requires 2870 kcal of energy for leading a normal life. The amount of cane-sugar in g must be consumed, if all the required energy has to be derived from the combustion of cane-sugar is:

[Given : The heats of formation for cane-sugar

(s)

C O_{2} (s)

and

H_{2} O (l)

are -530, -94.0 and -68.3 kcal respectively.]

Human body requires $2370 K . c a l$ of energy daily. If the heat of combustion of glucose is $- 790 K . c a l / m o l e$ the amount of glucose required for daily consumption is

N a C l O_{3}

is used even in spacecrafts to produce

O_{2}

. The daily consumption of pure

O_{2}

by a person is 492 L at

1 a t m

and

300 K

. How much amount of

N a C l O_{3}

in
grams, is required to produce

O_{2}

for the daily consumption of a person at STP?

N a C l O_{3} (s) + F e (s) \to O_{2} (g) + N a C 1 (s) + F e O (s)

N a C l O_{3}

is used, even in spacecrafts, to produce

O_{2}

. The daily consumption of pure

O_{2}

by a person is 492 L at 1 atm, 300 K. How much amount of

N a C l O_{3}

, in grams, is required to produce

O_{2}

for the daily consumption of a person at 1 atm, 300 K ?

N a C l O_{3} (s) + F e (s) \to O_{2} (g) + F e O (s) + N a C l (s)

R = 0.082 {L atm mol}^{- 1} K^{- 1}

Q. Per capita daily energy consumption of U.S.A. is

Join BYJU'S Learning Program

A person requires 2870Kcal of energy to lead normal daily life. If heat of combustion of cane sugar is −1349Kcal , then his daily consumption of sugar is:

The correct option is A 728gMolar mass of cane sugar (C12H22O11) is 342.2965 g/mol The Heat of combustion reaction for sugar.For 1 mol it is -1349 Kcal.For 2870 Kcal total moles would be = 2870/1349 = 2.127 moles. Weight of sugar =2.127×342=727.6=728g

A person requires $2870 K c a l$ of energy to lead normal daily life. If heat of combustion of cane sugar is $- 1349 K c a l$ , then his daily consumption of sugar is:

The correct option is A $728 g$
Molar mass of cane sugar $(C_{12} H_{22} O_{11})$ is 342.2965 g/mol

The Heat of combustion reaction for sugar.

For 1 mol it is -1349 Kcal.

For 2870 Kcal total moles would be = 2870/1349 = 2.127 moles.

Weight of sugar $= 2.127 \times 342 = 727.6 = 728 g$