A person running around a circular track of 10 m radius covers three-quarters of circumference, find his displacement.

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Solution

Here, displacement will be the shortest path between initial and final points and that is found here by Pythagoras theorem;

S = $\sqrt{(10^{2} + 10^{2})} = 10 \sqrt{2}$ m

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A person running around a circular track of 10 m radius covers three-quarters of circumference, find his displacement.

Here, displacement will be the shortest path between initial and final points and that is found here by Pythagoras theorem; S = √(102 +102 ) = 10√2 m

Here, displacement will be the shortest path between initial and final points and that is found here by Pythagoras theorem;

S = $\sqrt{(10^{2} + 10^{2})} = 10 \sqrt{2}$ m