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Question

A person's near point is 50 cm and his far point is 3 m. Power of the lenses he requires for (i) reading and
(ii) for seeing distant stars are

A
– 2 D and 0.33 D
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B
2 D and – 0.33 D
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C
– 2 D and 3 D
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D
2 D and – 3 D
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Solution

The correct option is B 2 D and – 0.33 D

For correcting the near point, required focal length

f=50×25(5025)=50 cm
so power p=10050=+2D

For correcting the far point, required focal length
f = -(far point of defective eye) = -3m

P=13D=0.33 D


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