Question

A person sells a table at a profit of $20\%$. If he had bought it at $10\%$ less cost and sold for Rs. $105$ more, he would have gained $35\%$. The cost price of the table is

• A. Rs. $7000$
• B. Rs. $7350$
• C. Rs. $9200$
• D. Rs. $8140$

Answer 1

The correct option is A Rs. $7000$

Let the C.P. of the table be Rs. x.
Then, S.P. of the table at 20% profit$=\frac{120}{100}\times Rs.x=Rs\frac{6x}{5}$
C.P. of the table at 10% loss $=\frac{90}{100}\times Rs.x$$=Rs\frac{9x}{10}$
S.P. of the table at 35% profit now$=\frac{135}{100}\times Rs\frac{9x}{10}$

Then according to the question

$\frac{6x}{5}+105=\frac{135}{100}\times \frac{9x}{10}$

$\Rightarrow \frac{6x}{5}+105=\frac{243}{200}x$

$\Rightarrow \frac{243}{200}x-\frac{6}{5}x=105$

$\Rightarrow \left(\frac{243-240}{200}\right)x=105$

$\Rightarrow x=\frac{105\times 200}{3}=Rs.7000$.