A person sells two articles together for $R s . 46$ , making a profit of $10$ on one and of $20$ on the other. If he had sold each article at $15$ profit, the result would have been the same. At what price does he sell each article?

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Solution

Let the CP of 1st article be x.

So,SP of 1st article $= x + \frac{x}{10} = \frac{11 x}{10} .$

And,SP of 2nd article $= 46 - x + 46 - \frac{x}{5} = \frac{6 (46 - x)}{5} .$

Therefore,SP of both articles $= \frac{11 x}{10} + \frac{6 (46 - x)}{5} = 552 - \frac{x}{10} .$

If he sold the article of 15% profit,total SP $= x + \frac{15 x}{100} + 46 - x + \frac{15}{100 (46 - x)} = \frac{529}{10} .$

Now,According to the question, $552 - \frac{x}{10} = \frac{529}{10}$

$x = 552 - 529 = 23.$

Therefore,SP of each article $= \frac{11}{10} * \frac{236}{5} * (46 - 23) .$

Amount $= R s 25.3 a n d R s .27 .6$ .

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A person sells two articles together for Rs. 46, making a profit of 10 on one and of 20 on the other. If he had sold each article at 15 profit, the result would have been the same. At what price does he sell each article?

A person sells two articles together for $R s . 46$ , making a profit of $10$ on one and of $20$ on the other. If he had sold each article at $15$ profit, the result would have been the same. At what price does he sell each article?