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Question

A person sitting on the top of a tall building drop balls at regular intervals of one second. Find the positions of the 3rd,4th and 5th ball when the 6th ball is being dropped.

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Solution

For every ball, u=0,a=g=9.8 m/s2

4th ball moves for 2 sec,5th ball 1 sec and 3rd ball 3 sec when 6th ball is being dropped.

For 3rd ball t=3 sec
S3=ut+12at2

=0+1/2(9.8)32

=4.9 m below the top.

For 4th ball t=2 sec
S2=0+1/2gt2

=1/2(9.8)22

=19.6 m below the top (u=0)

For 5th ball t=1 sec
S3=ut+1/2at2

=0+1/2(9.8)t2

=4.98 m below the top (u=0).

1373029_1094606_ans_370cc7559a0d43a3b33042b28b16f51c.png

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