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Question

A person speaking normally produces a sound Intensity of 40 dB at a distance of 1m. If the threshold Intensity for reasonable audibility is 20 dB, the maximum distance at which he can be heard clearly is:


A

4m

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B

5m

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C

10m

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D

20m

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Solution

The correct option is C

10m


40=10log10P4π(1)2I0 (i)

P – Power of sound energy of person

20=10log10(P4πx2I0) (ii)

(i) and (ii) gives 20 = 10log10x2

x=10 m


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