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Interference in Sound Waves

A person stan...

Question

A person standing at a distance of 6 m from a source receives sound wave in two ways, one directly from the source and other after reflection from a rigid boundary as shown in the figure. The maximum wavelength for which, the person will receive maximum sound intensity, is :

A

4 m

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B

\frac{16}{3} m

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C

2 m

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D

\frac{8}{3} m

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Solution

The correct option is A $4 m$
For the intensity to be maximum after interference, the path difference between the two waves must be an integral multiple of wavelength.

Hence, $(5 + 5) - 6 = n λ$

$⟹ λ = \frac{4}{n}$

This value is maximum for minimum value of $n$ , which is $1$ .

Therefore, $λ_{m a x} = 4 m e t e r s$

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