A person standing between a pair of tall and wide cliffs claps his hands. He hears the first two echoes at 2 sec and 3 sec respectively. If the speed of sound is 330 m/sec, then
Given that,
Speed of sound v=330 m/s
Time
t1=2s
t2=3s
Let d1= distance to near wall and d2 distance to far wall
Now, the distance to the near wall and back is
2d1=Speed×time=330×2
2d1=660m
Now, the distance is half
d1=330m
Now, the distance to the far wall and back is
2d2=330×3
2d2=990 m
The distance is half
d2=495m
Now, the total distance is
d=d1+d2
d=330+495
d=825m
Hence, the Separation between the cliffs is 825 m