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Question

A person standing near the edge of the top of a building throws two balls A and B. The ball A is thrown vertically upwards and B is thrown vertically downward with the same speed. The ball A hits the ground with a speed vA and the ball B hits the ground with a speed vB. Then,

A
vA>vB
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B
vA<vB
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C
vA=vB
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D
The relation between vA and vB depends on height of the building above the ground.
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Solution

The correct option is C vA=vB
The given condition can be represented as shown in the figure


So, we can say that the net displacement in both the cases is same i.e. h
So, from the third equation of motion we have,
v2u2=2as=2ah
Here, for both the cases, u,a=g and s=h are same
So, we can say that the final velocity of ball in both the cases will be same i.e. vA=vB

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