A person standing on the floor of an elevator drops a coin- The coin reaches the floor of the elevator in time t1 if the elevator is stationary and in time t2 if it is moving uniformly- Thena t1-t2b t1t2d t1t2 depending on whether the lift is going up or down-

(a) t1 = t2 After the coin is dropped, the nbsp;only force acting on it is gravity, which is same for both the cases. So t1 = t2. ...

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Standard VIII

Physics

Gravitational Force

A person stan...

Question

A person standing on the floor of an elevator drops a coin. The coin reaches the floor of the elevator in time t₁ if the elevator is stationary and in time t₂ if it is moving uniformly. Then
(a) t₁ = t₂
(b) t₁ < t₂
(c) t₁ > t₂
(d) t₁ < t₂ or t₁ > t₂ depending on whether the lift is going up or down.

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Solution

(a) t₁ = t₂

After the coin is dropped, the only force acting on it is gravity, which is same for both the cases.
So t₁ = t₂.

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(a) t1 = t2 After the coin is dropped, the only force acting on it is gravity, which is same for both the cases. So t1 = t2.

(a) t₁ = t₂

After the coin is dropped, the only force acting on it is gravity, which is same for both the cases.
So t₁ = t₂.