A person stands on a weighing machine kept on the floor of an elevator. When the elevator is at rest then the apparent weight of the person

is equal to their true weight

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is less than their true weight

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is more than their true weight

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can be more or less than their true weight

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Solution

The correct option is A is equal to their true weight
A man standing on a stationary lift will only experience a downward gravitational force and no pseudo force
$\Rightarrow F n e t = m g (d o w n w a r d s)$

As the net force is only gravitational force, so the apparent weight of the person will be equal to his true weight.

Hence correct answer is option $A$

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Similar questions

A person is standing in an elevator. In which situation will he find his weight less than his actual weight?

m

List I	List II
a) Lift is moving up with acceleration a	e) Apparent weight is greater than true weight
b) Lift is moving down with acceleration a	f) Apparent weight is zero
c) Lift is moving with uniformly velocity	g) Apparent weight is equal to true weight
d) Lift is freely falling	h) Apparent weight is less than true weight

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