A person starts from rest on amotorcycle with acceleration α and then retards with retardation β and comes to rest.The engine of a motorcycle can produce a maximum acceleration 5 m/s2. Its brakes can produce a maximum retardation 10 m/s2. What is the minimum time in which it can cover a distance of 1.5 km
If a body starts from rest with acceleration α and then regards with retardation β and comes to rest.
The total time for this journey is t and distance covered is S then
S=12αβt2(α+β)=125×10(5+10)×t2
⇒ 1500=125×10(5+10)×t2 ⇒ t=30 sec.